Question

2 2
13-12sin x,если cos x=0,11

Answer 1

$sin ^{2} x+cos ^{2}x=1, sin ^{2} x=1-cos ^{2}x =1-(0,11) ^{2} =0,9879$

sinx=+√0,9879  или  sin x= -√0,9879
13-12sinx=13-12√0,9879      или  13-12sin x=13+12√0,9879