Question

Вот,2 решите.

Answer 1

$1) 14a ^{5} b ^{7} -21a ^{4} b ^{8} -42a ^{3} b ^{9} = \ =7a^{3} b ^{7} (2a ^{2} -3ab-6b ^{2} ) \ \ 2)( x^{2} +1)(3 x^{5} y-y^{2} )-2x(3x^{5} y-y ^{2} )=(3 x^{5} y-y^{2} )( x^{2} +1-2x) =\ =(3 x^{5} y-y^{2} )( x-1)(x-1)$