Question

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81÷(√6-√3) ..........

Answer 1

$frac{81}{ sqrt{6}- sqrt{3} } = frac{81( sqrt{6}+ sqrt{3})}{( sqrt{6}- sqrt{3})( sqrt{6}+ sqrt{3}) } = frac{81( sqrt{6}+ sqrt{3})}{ 6-3 } =frac{81( sqrt{6}+ sqrt{3})}{ 3 } =27( sqrt{6}+ sqrt{3})$

Answer 2

$81:( sqrt{6}- sqrt{3} )= frac{81}{ sqrt{6} - sqrt{3} }= frac{81}{ sqrt{6}- sqrt{3} } * frac{ sqrt{6}+ sqrt{3} }{ sqrt{6}+ sqrt{3} } = frac{81( sqrt{6}+ sqrt{3} )}{ sqrt{6}^2- sqrt{3}^2 }= frac{81( sqrt{6}+ sqrt{3} )}{ 6-3 }$ = $frac{81( sqrt{6}+ sqrt{3} )}{ 2 } =27( sqrt{6}+ sqrt{3})$