Question

решите уравнение y(5y-6)=(3y+1)y

Answer 1

5у^2 - 6y = 3y^2  + y
5y^2 - 3y^2 - 6y - y = 0
2y^2 - 7y = 0
y(2y - 7) = 0
y = 0  2y - 7 = 0
         2y = 7
         y = 2/7

Answer 2

$y(5y-6)=(3y+1)y\ y(5y-6)-(3y+1)y=0\ y(5y-6-3y-1)=0\ y(2y-7)=0\ 2y-7=0 y=0\ 2y=7\ y=3,5$