Question

a) ( p + [  ] ) * ( [  ] - 3p + [  ] ) = p^3 + 27

b) ( [  ] - 2m ) * ( [  ] + 6mn + [  ] ) = 27n^3 - [  ]

Answer 1

$(p+3)*(p^2-3p+9)=p^3+27 \ (3n-2m)*(9n^2+6mn+4m^2)=27n^3-8m^3$