Question

помогите решить cos^(2)x=sin^(2)x

Answer 1

$cos^{2} x=sin^{2} x/:cos^{2} x \ 1=tg^{2} x \ tg^{2} x=1 \ tgx=1 \ x= frac{ pi }{4} + pi n \ tgx=-1 \ x=- frac{ pi }{4} + pi m$

$cos^{2} x neq 0 \ cos xneq 0 \ x neq frac{ pi }{2} + pi n$

n∈Z
m∈Z