Question

27+b^6
плизззззззззззззззззз

Answer 1

$27-b^{6}=3^{3}-(b^{2})^{3}=(3-b^{2})(9+3b^{2}+b^{4})$

Answer 2

$27+b ^{6} =3 ^{3} +(b ^{2} ) ^{3} =(b^{2}+3)(b ^{4} -3b+9)$