Question

Решите номер 21.Есть вложение.

Answer 1

1)x/(x-1)²-(x+2)/(x+2)(x-1) +2x/(x-6)=x/(x-1)²-1/(x-1) +2x/(x-6)=
=(x(x-6)-1(x-1)(x-6)+2x(x-1)²)/(x-1)²(x-6)=(x²-6x-x²=7x-6+2x³-4x²+2x)/(x-1)²(x-6)=
=(2x³-4x²+3x-6)/(x-1)²(x-6)=(2x²(x-2)+3(x-2))/(x-1)²(x-6)=(x-2)(2x²+3)/(x-1)²(x-6)
2)(x-2)(2x²+3)/(x-1)²(x-6) : 1/(2x-2)²=(x-2)(2x²+3)/(x-1)²(x-6) *4(x-1)²=4(x-2)(2x²+3)/(x-6)

Answer 2

Спасибо