Предмет: Алгебра, автор: р16

решите уравнение 2x^3+6x=7x^2

Ответы

Автор ответа: wik8947201

$\2x^3-7x^2+6x=0 \ \x(2x^2-7x+6)=0 \ \x(2x^2-4x-3x+6)=0 \ \x[2x(x-2)-3(x-2)]=0 \ \x(x-2)(2x-3)=0 \ \x=0 vee x-2=0 vee 2x-3=0 \ \x=0 vee x=2 vee x=1,5$

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