Предмет: Геометрия, автор: lalikk

найти площадь равнобокой трапеции описанной около окружности если её основания 8 и 18

Ответы

Автор ответа: NNNLLL54

Трапеция АВСД, ВС=8, АД=18.
АД+ВС=АВ+СД=8+18=26 ---> AB=CD=26:2=13
ΔABH (BH перпенд-но AD): AH=(AD-DC)/2=(18-8)/2=5
BH²=AB²-AH²=169-25=144, BH=12
S(трапеции)=(AD+BC)/2*(BH)=26/2*(12)=13*12=156

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