Question

y=-x в квадрате +4 и y=o

Answer 1

$y=-x^2+4\y=0\\-x^2+4=0,\\x^2-4=0\\(x-2)(x+2)=0\\x_1=-2,x_2=2$

Answer 2

$y=- x^{2} +4 \ y=0 \y=y \ x^{2} -4=0 \ x=4 \ x=+-2$