Question

Sinx*cosx+cos (в квадрате) x=0

Answer 1

sinx * cosx + cos^2x = 0 
cosx * ( sinx + cosx ) = 0 

# 1 
cosx = 0 ==> x = pi/2 + pik, k ∈ Z

# 2 
sinx + cosx = 0   I : cosx ≠ 0 
tgx + 1 = 0 
tgx = - 1 
x = - arctg (1) + pik
x = - pi/4 + pik, k ∈ Z

Ответ:
x = pi/2 + pik, k ∈ Z
x = - pi/4 + pik, k ∈ Z