Question

Решите 3-ий предел 4-го варината

Answer 1

$lim_{xto 2}frac{5-sqrt{27-x}}{2-x}=limfrac{(5-sqrt{27-x})(5+sqrt{27-x})}{(2-x)(5+sqrt{27-x})}=limfrac{25-27+x}{(2-x)(5+sqrt{27-x})}=\\=limfrac{-(2-x)}{(2-x)(5+sqrt{27-x})}=-lim_{xto 2}frac{1}{5+sqrt{27-x}}=-frac{1}{5+sqrt{25}}=-frac{1}{10}=-0,1$