Question

Lim стремящийся к бесконечности 
1)-4*(-1/5)^(n-1)
2) ((2n^2+5n+7)/(2n^2+5n+3))^n

Answer 1

$lim_{n to infty} -4*( frac{-1}{5})^{n-1} = lim_{n to infty} 4*( frac{-1}{5^{n}})*5=0$

$lim_{n to infty} (frac{2n^2+5n+7}{2n^2+5n+3})^n=$$lim_{n to infty} (frac{n^2(2+frac{5}{n} + frac{7}{n^2}}{n^2(2+ frac{5}{n} + frac{3}{n^2}})^n = 1^{n} = 1$