Question

Помогите пожайлуста.
³√(3x²-3)=³√8x

Answer 1

$sqrt[3]{(3x^2-3)} = sqrt[3]{(8x)} \ \ (3x^2-3)=(8x) \ \ 3x^2-8x-3=0 \ D=b^2-4ac=(-8)^2-4*3*(-3)=64+36=100 \ \ x_{1} = frac{-b+ sqrt{D} }{2a} = frac{8+10}{6} = frac{18}{6} =3 \ \ x_{2} = frac{-b- sqrt{D} }{2a} = frac{8-10}{6} = frac{-2}{6} = -frac{1}{3}$