Question

0,008^-1/3-(1/6)^-2+2561/2-2^-1+6,5

Answer 1

$0,008^{-frac{1}{3}}-left(frac{1}{6}right)^{-2}+frac{2561}{2}-2^{-1}+6,5\\=left(sqrt[3]{0,008}right)^{-1}-6^2+1280frac{1}{2}-frac{1}{2}+6,5\\=0,2^{-1}-36+1280+6,5\\=left(frac{1}{5}right)^{-1}+1250,5\\=5+1250,5=1255,5$