Question

Решить тригонометрическое уравнение

Answer 1

√2 sin17x=√6 cos17x
cos17x<>0 
sin17x/cos17x=√6/√2
tg 17x=√3
17x=π/3+πN
x=π/51+π/17*N

Answer 2

$sqrt{2}sin17x = sqrt{6} cos17x \ sqrt{2} tg17x= sqrt{6} \ tg17x= sqrt{3} \ 17x=arctg sqrt{3} + pi k \ 17x= frac{ pi }{3} + pi k \ x= frac{ pi }{51} + frac{ pi k}{17}$

k∈Z