Question

(18) в степени 0,5х-1=2

Answer 1

$( frac{1}{8})^{0,5x-1}=2 \ (2^{-3})^{0,5x-1}=2^{1} \ -3(0,5x-1)=1 \ -1,5x+3=1 \ -1,5x=-2 \ x=1 frac{1}{3}$