Question

Решите уравнение; $log _{3}( x^{2} - 7_{x}+12)= log_{3} 20$

Answer 1

$log_3(x^2-7x+12)=log_320\x^2-7x+12=20\x^2-7x-8=0\D=49+32=81\x_1=8;\x_2=-1$