Question

Система уравнений

$left { {{ 3^{x+y}=9 } atop { 4^{2x+y-1}=1 }} right.$

Answer 1

$left { {{ 3^{x+y}=9} atop { 4^{2x+y-1}=1}} right. \ 3^{x+y}=9 \ 3^{x+y} =3^2 \ x+y=2 \ y=2-x \ 4^{2x+2-x-1} =1 \ 4^{2x+2-x-1} =4^0 \ 2x+2-x-1=0 \ x=-1 \ 3^{-1+y}=3^2 \ -1+y=2 \ y=3$