Question

2 * sin^2 (x - 3pi/2) + sqrt3 * sin2x=0

Answer 1

2сosx+2√3sinnxcosx=0
2cosx(1+√3sinx)=0
cosx=0⇒x=π/2+πn
sinx=-1/√3⇒x=(-1)^n+1 *arcsin1/√3+πn