Question

Помогите решить уравнение!
1) 3х/3=1-x/2
2)1/3(5/12-4m)=4/9(1 1/2m-3/8)
3)x(-5)(x+2,5)=0

Answer 1

1)
$frac{3x}{3}=1-frac{x}{2} \ \ x=1-frac{x}{2} \ \ x+frac{x}{2}=1 \ \ frac{2x+x}{2}=1 \ \ 3x=2 \ \ x= frac{2}{3}$

2)
$frac{1}{3}(frac{5}{12}-4m)=frac{4}{9}(1frac{1}{2}m-frac{3}{8}) \ \ frac{1}{3}(frac{5-48m}{12})=frac{4}{9}(frac{12m-3}{8}) \ \ frac{5-48m}{12*3}=frac{12m-3}{2*9} \ \ frac{5-48m}{36}=frac{12m-3}{18} \ \ 18(5-48m)=36(12m-3) \ 5-48m=2(12m-3) \ 5-48m=24m-6 \ -48m-24m=-6-5 \ -72m=-11 \ m= frac{11}{72}$

3)
$x(-5)(x+2,5)=0 \ \ x(-5)(x+frac{25}{10})=0 \ \ x(-5)(x+frac{5}{2})=0 \ \ x(-5x-frac{25}{2})=0 \ x=0 \ \ -5x-frac{25}{2}=0 \ \ -5x=frac{25}{2} \ \ x=frac{25}{2}:(-5) \ \ x=frac{25}{2}*(-frac{1}{5}) =-frac{5}{2}$