Question

Дано:
 f(x)= x^2+2 - 2 sinx. Найдите f '(0).
         x+2

Answer 1

f`(x)=(2x(x+2)-1(x²+2))/(x+2)² -2cosx=(x²+4x-2)/(x+2)² -2cosx
f`(0)=-2/4-2cos0=-1/2-2=-2.5