Question

У=9х4-9х2+2=0 с осью ОХ

Answer 1

$9x^4-9x^2+2=0$
$x^2=t$
$9t^2-9t+2=0$
$D=81-72=9; sqrt{D}=3$
$t_1= frac{9-3}{18} = frac{1}{3}$

$t_2= frac{9+3}{18}= frac{2}{3}$

$x^2= frac{1}{3}$
$x_1= frac{1}{ sqrt{3} }$
$x_2= -frac{1}{ sqrt{3} }$

$x^2= frac{2}{3}$
$x_3= sqrt{ frac{2}{3} }$
$x_4= - sqrt{ frac{2}{3} }$

 Ответ:$- frac{1}{ sqrt{3} }; frac{1}{ sqrt{3} }; sqrt{ frac{2}{3}}; - sqrt{ frac{2}{3} } .$