Question

Неравенство и сис-ма уровнений помогите плз

Answer 1

$1); 9^{sqrt{x}}=(3^2)^{sqrt{x}}=(3^{sqrt{x}})^2=t^2,; t=3^{sqrt{x}}$

$t^2-10t+9<0\\t_1=1,t_2=9; (teor.; Vieta)$

$+ + + + (1)- - - - -(9)+ + + +$
$1<t<9$
$left {{{3^{sqrt{x}}>3^0}atop {3^{sqrt{x}}<3^2}} right. ; left { {{sqrt{x}>0} atop {sqrt{x}<2}} right. ; left { {{x>0} atop {x<4}} right. \\xin (0,4)$

$2)left { {{x^2y^2=2x^4-1} atop {x^2y^2=3x^4-2}} right.$

$2x^4-1=3x^4-2\\x^4=1; to ; x^2=1; to ; x=pm 1\\ a); left { {{x=-1} atop {2=y^2+1}} right. ; left { {{x=-1} atop {y^2=1}} right. ; left { {{x=-1} atop {y=pm 1}} right. \\b); left { {{x=1} atop {2=y^2+1}} right. ; left { {{x=1} atop {y=pm 1}} right. \\Otvet:; (-1,-1),; (-1,1),; (1,-1),; (1,1).$<9,;>