Question

(a-(4a-9/a-2))/(2a-(2a/a-2))

Answer 1

$frac{a-(4a- frac{9}{a}-2)}{2a-frac{2a}{a-2}} \ \ \ a-(4a- frac{9}{a}-2)=a-4a+ frac{9}{a}+2=-3a+ frac{9}{a}+2=frac{-3a^{2}+2a+9}{a} \ \ \ 2a-frac{2a}{a-2}=frac{2a(a-2)-2a}{a-2}=frac{2a^{2}-4a-2a}{a-2}=frac{2a^{2}-6a}{a-2} \ \ \ frac{-3a^{2}+2a+9}{a}:frac{2a^{2}-6a}{a-2}=frac{-3a^{2}+2a+9}{a}*frac{a-2}{2a^{2}-6a}=frac{(-3a^{2}+2a+9)(a-2)}{a(2a^{2}-6a)}= \ \ =frac{-3a^{3}+6a^{2}+2a^{2}-4a+9a-18}{2a^{3}-6a^{2}}=frac{-3a^{3}+8a^{2}+5a-18}{2a^{3}-6a^{2}}$

Answer 2

Спасибо