Question

решите неравенство 16x2>1

Answer 1

$16x^2>1\\16x^2-1>0\\(4x-1)(4x+1)>0\\x_1=frac{1}{4},; x_2=frac{-1}{4}\\+ + + + (-frac{1}{4})- - - - -(frac{1}{4})+ + + + \\xin (-infty;-frac{1}{4})U(frac{1}{4};+infty)$