Question

решите систему неравенств 2х^2+у^2=36; 8х^2+4у^2=36х

Answer 1

$displaystyle left { {{2x^2+y^2=36} atop {8x^2+4y^2=36x |:4}} right. \\ left { {{2x^2+y^2=36} atop {2x^2+y^2=9x}} right. \\36=9x\\x=4\\2*4^2+y^2=36\\32+y^2=36\\y^2=4\\ y=pm 2 \\Otvet (4;2) (4;-2)$