Question

(sin2x)/(cos(3pi/2 +x))=1

Answer 1

Решение.
sin2x = cos(x-3п/2); 
2sinx•cosx+sinx=0 
sinx•(2cosx+1) =0 
1)sinx=0 => x=πn 
2)cosx=-½ => x=π±π/3+2πn