Question

решите систему уравнений
(2-x)/3-(y+6)/6=0
x+2y=-1

Answer 1

$left { {{frac{2-x}{3}-frac{y+6}{6}=0} atop {x+2y=-1}} right. \ left { {{frac{4-2x-y-6}{6}=0} atop {x+2y=-1}} right. \ left { {{-2x-y-2=0} atop {x+2y=-1}} right. \ left { {{-2x-y=2} atop {x+2y=-1}} right. (*2)\ left { {{-4x-2y=4} atop {x+2y=-1}} right. (+)\ -3x=3\ x=-1\ -1+2y=-1 => y=0$
Ответ: х=-1; у=0