Предмет: Химия, автор: Lulu1995

Напишите математическое выражение для скорости реакции:
2SO2+O2=2SO3
Как изменится скорость реакции при увеличении давления в 2 раза.

Ответы

Автор ответа: vikuka

Начасльная скорость реакции (математическое выражение):
v₀ = k * [SO₂]² * [O₂]
Если давление в системе возрастет в 2 раза, то и концентрация газов увеличится в 2 раза, тогда
v = k * [SO₂]² * [O₂] = k * [2SO₂]² * [2O₂] =k * 2²*2*[SO₂]² * [O₂] =k *8* [SO₂]² * [O₂],
v /v₀ = k *8* [SO₂]² * [O₂] ÷ k * [SO₂]² * [O₂] = 8
то есть скорость реакции возрастет в 8 раз.

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