Question

решите неравенство tg(2x+п/6)>-√3

Answer 1

-π/3+πn<2x+π/6<π/2+πn
-π/3-π/6+πn<2x<π/2-π/6+πn
-π/2+πn<4x<π/3+πn
-π/8+πn/4<x<π/12+πn/4
x∈(-π/8+πn/4;π/12+πn/4)

Answer 2

Спасибо!