Question

-2sin2x+2sinx=0, помогите решить

Answer 1

sin2x=2sinxcosx

-2(2sinxcosx)+2 sinx=0

-4sinxcosx+2sinx=0 |:(-2)

2sinxcosx-sinx=0

sinx(2cosx-1)=0

sinx=0                                                           2cosx=1

x=Пиn(число пи умноженное на n)                 cosx=1/2

                                                                     x=пи/3 +2пиn

                                                                     x=5пи/3+2пиn