Question

-10/sin^2 92+sin^2 182 

Answer 1

sin^2(182) = sin^2(92+90) = (sin92*cos90 + sin90*cos92)^2 = cos^2(92)
-10/(sin^2(92) + sin^2(182)) = -10/(sin^2(92) + cos^2(92)) = -10/1 = -10