Question

(у-8)(2y-1)-(3y+1)(5y-2)

Answer 1

$(y-8)(2y-1)-(3y+1)(5y-2)=\\(2y^2-16y-y+8)-(15y^2-6y+5y-2)=\\2y^2-17y+8-15y^2+y+2=\\-13y^2-16y+10$