Question

Решить уравнение!
1) 3х(х-2)=4х+7

Answer 1

$3x(x-2)=4x+7\3x^2-6x=4x+7\3x^2-10x-7=0\D=100-4cdot(-21)=100+84=184=2sqrt{46}\x_1=frac{10+2sqrt{46}}{2*3}=frac{2(5+sqrt46)}{6}=frac{5+sqrt46}{3}\x_2=frac{10-2sqrt46}{6}=frac{2(5-sqrt46)}{6}=frac{5-sqrt46}{3}$

Answer 2

$\3x^{2}-6x=4x+7\ 3x^{2}-10x-7=0\ D=10^{2}-4cdot3cdot(-7)=184=(2sqrt{46})^{2}\ x_{1}=frac{10-2sqrt{46}}{6}=frac{5-sqrt{46}}3}\ x_{2}=frac{5+sqrt{46}}{3}$