Question

12cos50+6cos70 / корень из 3*sin70

Answer 1

(12cos50 + 6sin70)/(√3sin70) =

= (12sin40 + 12((1/2)cos70 + (√3/2)sin70)) - 12(√3/2)sin70)/(√3sin70) =

= 12(sin40 + sin100)/(√3sin70) - 6 =

= 12(2sin70cos30)/(√3sin70) - 6 =

= 12 - 6 = 6;

Answer 2

Решение во вложении:

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