Question

lg*(2-x)=2*lg*4-lg*2

Answer 1

lg(2-x)=2lg4-lg2
lg(2-x)=2lg4/2
lg(2-x)=2lg2
2lg2-lg(2-x)=0
2lg2/(2-x) =0
lg(2/(2-x))^2-0
lg(2/(2-x))^2=lg1
(2/(2-x))^2=1
4/(2-x)^2=1
(2-x)^2=4
4-4x+x^2-4=0
x^2-4x=0
х(х-4)=0
x=0 или х=4
Ответ: 0; 4