Предмет: Алгебра, автор: vikastigmata

$log_{2} 128*log _{6} 36$

Ответы

Автор ответа: Аноним

0

$log_{2}128*iog_{6}36=log_{2}2^{7}*log_{6}6^{2}=7*2=14 \$

Автор ответа: mmb1

0

log_2 128 * log_6 36=log_2 2^7 * log_6 6^2=7*2=14

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