Question

Сократить дробь

$frac{(3x-6)^{2}}{3x^{2}+3x-18}$

Answer 1

((3х-6)^2)/(3x^2+3x-18)=(9*(x-2)^2)/(3*(x^2+x-6))=(9*(x-2)^2)/(3*(x+3)*(x-2))=       =3(x-2)/(x+3)=(3x-6)/(x+3)