Question

решите уравнение (x+4)^2-(x+1)(x-2)=2x-3

Answer 1

(x+4)²-(x+1)(x-2)=2x-3
х²+8х+16-х²+2х-х+2-2х+3=0
7х+21=0
7х=-21
х=-21:7
х=-3
Ответ:-3

Answer 2

(x+4)^2-(x+1)(x-2)=2x-3
x^2+8x+16 - (x^2 - x - 2) - 2x + 3 = 0 
x^2 + 8x + 16 - x^2 +x + 2 - 2x + 3 = 0 
7x + 21 = 0
7x = - 21
x = - 3