Question

помогите решить*
20mn-4m^2/m^2-10mn+25n^2
30p^7 q^9 t / 24p^7 q^8 t^3

Answer 1

$frac{20mn-4m^2}{m^2-10mn+25n^2}=frac{4m(5n-m)}{(5n-m)^2}=frac{4m}{5n-m}\\frac{30p^7q^9t}{24p^7q^8t^3}=frac{5q}{4t^2}$