Question

-3log_(0,25)x  6 решите неравенство

Answer 1

$-3log_{frac{1}{4}}x leq 6; ,; ODZ:x>0\\3log_4x leq 6\\log_4(x^3) leq 6; ,; ; 6=log_4(4^6)\\x^3 leq 4^6; ,; ; 4^6=(4^2)^3=16^3\\x^3-16^3 leq 0\\(x-16)(x^2+16x+256) leq 0\\x^2+16x+256>0; pri; xin R,; t.k.D=-768<0\\x-16 leq 0\\x leq 16\\Otvet:; 0<xleq16$