Question

Решите систему:
x-y=2
x^2-xy+y^2=7

Answer 1

$begin{cases}x-y=2=>x=y+2\x^2-xy+y^2=7end{cases}\\(y+2)^2-y(y+2)+y^2=7\y^2+4y+4-y^2-2y+y^2=7\y^2+2y-3=0\y_1=-3 ;y_2=1\x_1=-1 ;x_2=3\\OTBET:(-1;-3);(3;1)$