Question

x+2<5x-2(x-3)

4(x+8)-7(x-1)<12

Answer 1

x+2<5x-2(x-3)                       4(x+8)-7(x-1)<12

x+2<5x-2x+6                         4x+32-7x+7<12

x-3x<6-2                               -3x<-27

-2x<4                                    x>9

x>-2                                      (9;+бесконечность)

(-2; +бесконечность)

 

 

Answer 2

x+2<5x-2(x-3)

х-5х+2х<6-2

-2х<4

х>-2

х∈(-2;+∞)

4(x+8)-7(x-1)<12

4х+32-7х+7<12

-3х<12-32-7

3х<27

х>9

х∈(9;+∞)