Question

помогите!!! срочно надо!!!!)))

Answer 1

3. sqrt(log2(2x^2)*log2(16x)/log2(4))=sqrt(1/2(1+log2(x^2))(4+log2(x));

(1+2log2(x))(4+log2(x))=9/4log2(x)

log2(x)=t

2(2t^2+9t+4)=9t^2

5t^2-18t-8=0

t1=4

t2=-2/5

log2(x)=4  x=16

log2(x)=-0,4  x=1/2^(0.4)

(1+2t)>0

(1+t)>0