Question

Решить уравнение.

(8x-3)(2x+1)=(4x-1)2

Answer 1

16x^{2}+2x-3=8x-2

 16x^{2} -6x-1=0

D=36+64=100

x1=(6+10)/32=0.5

x2=(6-10)/32=-1/8 

 

Answer 2

(8x-3)(2x+1)=(4x-1)2

16x^2+8x-6x-3=8x-2

D=b^2-4ac

D=36-4*(-16)=36+64=100=10^2

x1=(6+10)/(32) = 1/2

x2=(6-10)/(32) = -1/8