Question

решите уравнение сos (х+П/6)=-1/2

Answer 1

сos (х+П/6)=-1/2

x+π/6=2π/3+2πn       x+π/6=-2π/3+2πn
x=2π/3-π/6+2πn        x=-2π/3-π/6+2πn
x=π/2+2πn                x=-5π/6+2πn

Answer 2

сos (х+П/6)=-1/2
х+π/6=+- (π-π/6)+2πn, n∈Z
x+π/6=+-5π/6 +2πn, n∈Z
x=+-5π/6 - π/6 +2πn, n∈Z
x1=5π/6-π/6+2πn, n∈Z            x2=-5π/6-π/6+2πn, n∈Z
x1=2π/3+2πn, n∈Z                   x2=-π+2πn, n∈Z