Question

Помогите решить пожалуйста
(√6-√2)²+√48

Answer 1

$(sqrt{6}-sqrt{2})^2+sqrt{48}=\\(sqrt{6})^2-2*sqrt{6}*sqrt{2}+(sqrt{2})^2+sqrt{4*6*2}=\\6-sqrt{4}*sqrt{6}*sqrt{2}+2+sqrt{4}*sqrt{6}*sqrt{2}=8$