Question

помогите решить:
x^6-14x^4+56x^2-64=0

Answer 1

$x^{2} =y \ y^{3} -14y ^{2} +56y-64=0 \ y^{3} -8 y^{2} -6y ^{2}+48y+8y-64=0 \ y^{2} (y-8)-6y(y-8)+8(y-8)=0 \ y-8=0 \ y_{1} =8 \ y^{2} -6y+8=0 \ D>0 \ y_{2} =4 \ y _{3}=2 \ x^{2} =8 \ x_{1} =- sqrt{8} \ x_{2} = sqrt{8} \ x^{2} =4 \ x_{3} =-2 \ x_{4} =2 \ x^{2} =2 \ x_{5} =- sqrt{2} \ x_{6} = sqrt{2}$